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let a=x/1-x
then 1/a=1-x/x
so
7√a+8√1/a=15
squaring both sides
we get
as we know that
(a+b)^2=a^2+b^2+2ab
so
(7√a+8√1/a)^2=225
(49a + 64/a + 2×7×8√a×1/a)=225
49a+64/a+112√1=225
49a+64/a+112-225=0
49a+64/a-113=0
multiplying both sides with a
we get
49a^2+64-113a=0
49a^2-49a-64a+64=0
49a(a-1)-64(a-1)=0
a=1
and
a=64/49
as we know
when a=1
a=x/1-x
1=x/1-x
1-x=x
x=1/2
when a=64/49
x/1-x=64/49
x=64/113
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Anonymous:
Thank you so much dude
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