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Since, OA || BC and OB is transversal,
∠AOB = ∠CBO [Alternate interior angles]
⇒∠AOB=80°
If an arc subtends an angle 2Ф at the the centre of the circle then, it subtends an an angle of Ф at any point on the circumference of the circle.
Here, arc AB subtends central angle of 80°.
So, it must subtend an angle of 40° at the circumference.
∴∠ACB = 40°
∠AOB = ∠CBO [Alternate interior angles]
⇒∠AOB=80°
If an arc subtends an angle 2Ф at the the centre of the circle then, it subtends an an angle of Ф at any point on the circumference of the circle.
Here, arc AB subtends central angle of 80°.
So, it must subtend an angle of 40° at the circumference.
∴∠ACB = 40°
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