Question

help me to find this answer
I will mark ​

Answer 1

We're given,

$A=\left[\begin{array}{ccc}2&3&1\\ 0&-1&3\end{array}\right]\quad;\quad B=\left[\begin{array}{c}4&-1&5\end{array}\right]$

Well, A × B is possible, because the no. of columns in A and that of rows in B are equal, 3.

But B × A is not possible because the no. of columns in B is 1 while the no. of rows in A is 2.

So,

$\begin{aligned}&A\times B\\ \\ \Longrightarrow\ \ &\left[\begin{array}{ccc}2&3&1\\ 0&-1&3\end{array}\right]\times\left[\begin{array}{c}4&-1&5\end{array}\right]\\ \\ \Longrightarrow\ \ &\left[\begin{array}{c}(2\cdot 4)+(3\cdot-1)+(1\cdot 5)\\ (0\cdot 4)+(-1\cdot -1)+(3\cdot 5)\end{array}\right]\\ \\ \Longrightarrow\ \ &\left[\begin{array}{c}8-3+5\\ 1+15\end{array}\right]\\ \\ \Longrightarrow\ \ &\boxed{\left[\begin{array}{c}10\\ 16\end{array}\right]}\end{aligned}$

Answer 2

$\huge\textbf{Answer:-}$

Answer in the attachment:-

explained answer given :-