Question

Help me to find this plz​

Answer 1

Answer:

In triangle xyz and xpz,

I) xy = xp (given)

II) angle y = angle p (given, each 90°)

III) xz = xz (common side)

===》triangle XYZ congruent to triangle XPZ (RHS Criteria)

Step-by-step explanation:

Hope it helps you :)

Answer 2

Question :-

8. In the given figure prove that

i.) ∆XYZ ≅ ∆XPZ

Solution :-

Here are some points which will prove congruency of these two triangles -

1. ∠XYZ = 90°

∠XPZ = 90°

So, ∠XYZ = ∠XPZ = 90°. Both are right angles.

2. Side XY = Side XP

XY is the hypothenuse of the triangle XYZ.

XP is the hypothenuse of the triangle XPZ.

(Given in the picture)

3. In ∆XYZ and ∆XPZ,

Side XZ is common.

From the above mentioned points, it can be concluded that

∆XYZ ≅ ∆XPZ by RHS Axiom.

Hence, Proved.

Note :-

• RHS Axiom means Right angle, Hypothenuse, Side Axiom.

• Meaning of signs used in the answer.

➝ ∆ - it is showing triangle.

➝ ≅ - it is congruency sign.

➝ ∠ - it is showing angle.