help me to..... find x and y........
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Since it's a parallelogram,
Opposite sides are equal
So PQ = RS and PS = QR ------eq(1)
Given,
PQ = 5x
PS = 47
RS = 25
QR = 3y-1
Substitute PQ,PS,RS and QR in eq(1),
PQ=RS
5x=25
x = 25/5
x = 5
And
PS=QR
47=3y-1
3y-1 = 47
3y = 48
y = 48/3
y = 16
Hence,x = 5 and y = 16
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