Question

help me to solve the question B..

Don't post not something about answer..​

Answer 1

Answer:

Let ABCDE be your regular pentagon. Let γ be the circle passing through ABC, and let O be the center of γ.

First, you can prove that the triangles ABO and BCO are congruent, because they have the same sides.

Then you can prove that the triangles BCO and CDO are congruent, using the fact thatBC≅CD

BO≅CO

^OBC=^ABC−^ABO≅^BCD−^BCO=^OCD

Thus OD≅OC, and you proved that D∈γ.

In a similar way you can prove that E∈γ as well, the proof repeats using the triangles CDO and DEO.

EDIT: The same proof applies to any N-sided regular polygon A1A2…AN. You fix the circle γ passing through A1,A2,A3 and prove that A4∈γ. This means that γ is the circle through A2,A3,A4, and you prove that A5∈γ. Then repeat recursivley until you get AN∈γ

Answer 2

Answer:

such a long questions in maths

Step-by-step explanation:

then only 5 points impossible for