Math, asked by shahidimran90, 1 month ago

HELP ME TO SOLVE THIS ​

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Answers

Answered by SandySanjeet
1

Answer:

B !

Step-by-step explanation:

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Answered by pinakiparbatihembram
0

Answer:

Option (A) is correct answer.

Step-by-step explanation:

Area of ABC = 1/2 × base× height

= 1/2×21 cm × 20 cm

=

=210cm^2

Using Heron's formula

Let CD = a = 42 cm

AC = b = 20 cm

AD = c = 34 cm

Semi perimeter of ACD (s) = a+b+c

2

= 42cm+ 20cm + 34cm

2

= 96cm

2

= 48cm

AREA OF ACD = s (s-a) (s-b) (s-c)

= 48 (48-42)(48-20)(48-34)cm^2

= 48(6)(28)(14) cm^2

= 3×4×4× (3×2)(2×2×2×7)( 2×7) cm^2

= 2×2×2×2×3×3×4×4×7×7 cm^2

= 2×2×3×4×7 cm^2

= 336cm^2

AREA OF QUADRILATERAL ABCD = Area of ABC + Area of ACD

= 210cm^2 + 336cm^2

= 546cm^2

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