help me to solve this!!!!!!!!!
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log(y)x=5
=>x=y^5--------(i)
Again, log(2y)8x=4
=>8x=(2y)⁴
=>x=2y⁴
=>y^5=2y⁴ [from equation (i)]
=>y=2
Now let's put "y=2" in equation (i)
x=2^5
=>x=32
=>x=y^5--------(i)
Again, log(2y)8x=4
=>8x=(2y)⁴
=>x=2y⁴
=>y^5=2y⁴ [from equation (i)]
=>y=2
Now let's put "y=2" in equation (i)
x=2^5
=>x=32
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answer is is in attachment
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