Question

help me to solve this​

Answer 1

Answer:

Correct option is

A

True

k

2

x

2

−2(2k−1)x+4=0

⇒ Here, a=k

2

,b=−2(2k−1),c=4

⇒ It is given that roots are real and equal.

∴ b

2

−4ac=0

⇒ [2(2k−1)]

2

−4(k

2

)(4)=0

⇒ 4(4k

2

−4k+1)−16k

2

=0

⇒ 16k

2

−16k+4−16k

2

=0

⇒ −16k=−4

∴ k=

4

1

∴ We can see value of k given in question is correct.