help me to solve this
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deepak3317:
Hiiii riya
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Answered by
2
Answer:
Step-by-step explanation:
Given ,
Hello,
2√45+3√20/2√5;
=√5×[2√45+3√20/2√5];
=√5×(2√45+3√20/2)/2×(√5×√5);
=2√45·5+3√20·5/2×5;
=2√9·5·5+3√4·5·5/10;
=2√9·25+3√4·25/10;
=2×3×5+3×2×5/10;
=30+30/10;
=60/10;
=6..
It's rational number
Hope it helps you my dear friend..
Answered by
1
given,
(2√45 +3√20)/2√3 = (2√3√15 + 3√20)/2√3
= (2√15 + √3√20)/2
= (2√15 + √60)/2
= (2√15 + √4×√15)/2
= (2√15 + 2√15)/2
= (√15 + √15)
= 2√15
hence,
2√15 is an irrational number
(2√45 +3√20)/2√3 = (2√3√15 + 3√20)/2√3
= (2√15 + √3√20)/2
= (2√15 + √60)/2
= (2√15 + √4×√15)/2
= (2√15 + 2√15)/2
= (√15 + √15)
= 2√15
hence,
2√15 is an irrational number
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