Question

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Answer 1

Key Points :

When resistors are connected in series ,

$\sf \bigstar\ \; \pink{R_{eq}=R_1+R_2+R_3+...}$

When resistors are connected in parallel ,

$\bigstar\ \; \sf \blue{\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}+\dfrac{1}{R_3}+...}$

Solution :

Find attachments carefully .

R₂ , R₃ are connected in series ,

$\to \sf R_{23}=R_2+R_3\\\\\to \sf R_{23}=2+2\\\\\to \sf R_{23}=4\ \Omega$

R₂₃ , R₄ are connected in parallel ,

$\to \sf \dfrac{1}{R_{234}}=\dfrac{1}{R_{23}}+\dfrac{1}{R_4}\\\\\to \sf \dfrac{1}{R_{234}}=\dfrac{1}{4}+\dfrac{1}{1}\\\\\to \sf \dfrac{1}{R_{234}}=\dfrac{5}{4}\\\\\to \sf R_{234}=\dfrac{4}{5}\ \Omega$

Likewise ,

R₇ , R₈ are connected in series .

$\to \sf R_{78}=R_7+R_8\\\\\to \sf R_{78}=2+2\\\\\to \sf R_{78}=4\ \Omega$

R₇₈ , R₉ are connected in parallel ,

$\to \sf \dfrac{1}{R_{789}}=\dfrac{1}{R_{78}}+\dfrac{1}{R_9}\\\\\to \sf \dfrac{1}{R_{789}}=\dfrac{1}{4}+\dfrac{1}{1}\\\\\to \sf \dfrac{1}{R_{789}}=\dfrac{5}{4}\\\\\to \sf R_{789}=\dfrac{4}{5}$

Now ,

R₁ , R₂₃₄ , R₅ , R₆ , R₇₈₉ , R₁₀ are connected in series ,

$\to \sf R_{12345678910}=R_1+R_{234}+R_5+R_6+R_{789}+R_{10}$

$\to \sf R_{AB}=1+\dfrac{4}{5}+1+1+\dfrac{4}{5}+1\\\\\to \sf R_{AB}=4+\dfrac{8}{5}\\\\\to \sf R_{AB}=\dfrac{28}{5}\\\\\to \sf \orange{R_{AB}=5.6\ \Omega}\ \; \bigstar$

Answer 2

Answer:

Consider the mathematical statement:

−25 + 0 = 0 − ____

Which of the following integers makes the above statement correct?

Option 1: 0

Option 2: 52

Option 3: -25

Option 4: 25

Step-by-step explanation:

pleassee answer