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CONSTRUCTION :- JOIN DC AND BE
i) angle CAB = angle BAC
60° + angleBAC = 60° + angleBAC
angleDAB + angleBAC = angleEAC + angleBAC
angleDAC = angleEAB
ii) In ∆ADC and ∆AEB, we have,
1) AD = AB
2) AE = AC
3) angleDAC = angleEAB
.: ∆ADC CONGRUENT TO ∆AEB
Or, DC = BC
HENCE PROVED.
i) angle CAB = angle BAC
60° + angleBAC = 60° + angleBAC
angleDAB + angleBAC = angleEAC + angleBAC
angleDAC = angleEAB
ii) In ∆ADC and ∆AEB, we have,
1) AD = AB
2) AE = AC
3) angleDAC = angleEAB
.: ∆ADC CONGRUENT TO ∆AEB
Or, DC = BC
HENCE PROVED.
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