Math, asked by saicharannemaliga52, 8 months ago

help me to solve this problem ​

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Answers

Answered by Anonymous
1

Answer:

(2,-5/3) and  (0,-7/3)

Step-by-step explanation:

See the formula attached.

x1 = 4, x2= -2, y1= -1, y2= -3

Say the trisection points are A and B. now A divides the Line in 1:2 ratio and B divides by 2:1 ratio.

To find A : m=1 and n=2, putting values into formula:

A= (\frac{1*(-2)+ 2*4}{1+2} , \frac{1*(-3)+ 2*(-1)}{1+2}) = (2,-5/3)

To find B: m=2 and n= 1, putting values in formula:

B =(\frac{2*(-2)+ 1*4}{2+1} , \frac{2*(-3)+1*(-1)}{2+1}) = (0,-7/3)

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Answered by Anonymous
0

Answer:

❣ ANSWER ❣

✡ ROCKY HERE ✌

A ( 4 , - 1 ) and B ( -2 , - 3 )

x =  \frac{mx2 + nx1}{m + n}  \\ x =  \frac{1( - 2) + 1(4)}{2}  \\ x =  \frac{ - 2 + 4}{2}  \\ x =  \frac{2}{2}  \\ x = 1

y =  \frac{my2 + ny1}{m + n}  \\ y =  \frac{1( - 3) + 1( - 1)}{2}  \\ y =  \frac{ - 3 - 1}{2}  \\ y =  \frac{ - 4}{2}  \\ y =  - 2

✴HAPPY TO HELP YOU

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