Question

Help me to solve this question ​

Answer 1

Answer:

......................

Answer 2

Step-by-step explanation:

1)27a^3+64b^3+36ab(3a+4b)

use (a+b)^3 formula

(a+b)^3

=a^3+b^3+3ab(a+b)

2) (((2^2)^1/3)^1/4)

2^(2*(1/3)*(1/4))

2^(1/6)

3)(1) terminating since 36/100=0.36

(2) non terminating recurring since

1/11=0.09090909......

(3) terminating since

that is= 33/8=4.125