Question

Help me to solve this question ​

Answer 1

Answer:

X = 3 and y = 1

...........

Answer 2

Answer:

${3}^{x + y} = 81 \\ = > {3}^{x + y} = {3}^{4} \\ = > x + y = 4 \: \: ....(1) \: \: | as \: base \: is \: same \: on \: both \: side | \\ \\ {81}^{x - y} = {3}^{8} \\ = > {3}^{4 \times (x - y)} = {3}^{8} \\ = > 4 \times (x - y) = 8 \\ = > x - y = \frac{8}{4} \\ = > x - y = 2 \: \: \: .....(2) \\ \\ adding \: equation \: (1) \: and \: (2) \: \: we \: get \\ x + y = 4 ......(1) \\ x - y = 2 \: \: ......(2) \\ ........................ \\ 2x = 6 \\ = > x = \frac{6}{2} \\ = > x = 3 \: \\ \\ putting \: the \: value \: of \: x \: in \: equation \: (1) \\ x + y = 4 \\ = > 3 + y = 4 \\ = > y = 4 - 3 \\ = > y = 1$

X =3

y = 1 Ans.