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in triangle ABD and ACE
angleDAB = angleEAC (60 degree)---eq.1
angleA=angleA. (common) eq.2
by adding eq. 1 and 2 we get
angleDAC=angleEAC
hence proved
angleDAB = angleEAC (60 degree)---eq.1
angleA=angleA. (common) eq.2
by adding eq. 1 and 2 we get
angleDAC=angleEAC
hence proved
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