Question

help me to solve this sum
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Answer 1

Step-by-step explanation:

We have to find determinant here

${x}^{2} - 12 = 0 + 4x$

${x}^{2} - 4x - 12 = 0$

${x}^{2} - 4x + 3x - 12 = 0$

$x(x - 4) + 3(x - 4) = 0$

$(x - 4)(x + 3) = 0$

So separating both and equating them to 0 we get

$x = 4 \: \: and \: \: x = - 3$

Answer 2

Answer:

answer 0

Step-by-step explanation:

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