Question

help me tomorrow is my exam

Example 14: The digits of a two-digit number differ by 3. If the digits are in
and the resulting number is added to the original number, we get 143. What
original number?​

Answer 1

Answer:

Let the unit digit be x

Tens digit => x+3

10(x+3)+x

digits interchanged =10x+x+3

10(x+3)+x+10x+x+3=143

=> 10x+30+12x+3=143

=> 22x+33=143

22x=143−33

22x=110

x=11022

x=5

Original number = 85