HELP ME WITH 5 & 6.!
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5) applying L hospitals rule differentiate numerator and denominator and then put the limit
d/dx of Tanax=a( sec²ax)
and d/dx of X =1
now limit x tends 0 a(sec²ax)=a(sec0)²=a
d/dx of Tanax=a( sec²ax)
and d/dx of X =1
now limit x tends 0 a(sec²ax)=a(sec0)²=a
talibbeiggcet:
similarly do for 6 but differentiate it twice and then put limit directly so that indeterminate form vanishesan
if it really helps u then select it as brainliest answer
yup THANK U.
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