Question

Help me with it please... Need the solution!!

Answer 1

Energy stored when stretching 5 cm

E=1/2 kx^2

= 1/2*5*10^3*(5*10^-2)^2

=6.25

Energy stored when stretching 10 cm

E= 1/2*5*10^3*(10*10^-2)^2

=25

work done = change in energy = 25-6.25

=18.75