help me with problem 12 please
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Hey friend...
Here is your answer...
A : - Eq. Of area of rect. A = (x-1)(x+6)
A=x^2 +5x-6
Eq.of area of rect. B=3(x+3)
B=3x+9
B:- both have same area
3x+9 = x^2 +5x-6
x^2 +2x-15 = 0
On solving this eq.
x = - 5 and 3
Therefore, x=3
HOPE that it will help you
Answered by
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have your answer friend
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