Question

Help me with question Number 10

Answer 1

Hi there
Here's the answer:

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Given,
$W = 800\: kg$
$A_{1} = 10\: cm^{2}$
$A_{2} = 10\: m^{2} = 10 × 10^{4}\: cm^{2}$

Pressure in a liquid is divided equally so we can say pressure at both the Pistons should be same

$Pressure = \frac{Force}{Area}$

$\implies \frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{2}}$

Here,
$F_{1} = F$
$F_{2} = 8000\: N$
(Since F= m×a = m×g; 800 kg× 10m/s= 8000 kg-m/s = 8000 N)
(Took g = 10 m/s)

Substitute Values, we get

$\implies \frac{F}{10} = \frac{8000}{10×10^{4}}$

$\implies F = 0.8\: N$

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Answer 2

Answer:

Hi there

Here's the answer:

°•°•°•°•°<><><<><>><><>°•°•°•°•°

Given,

W = 800\: kgW=800kg

A_{1} = 10\: cm^{2}A

1

=10cm

2

A_{2} = 10\: m^{2} = 10 × 10^{4}\: cm^{2}A

2

=10m

2

=10×10

4

cm

2

Pressure in a liquid is divided equally so we can say pressure at both the Pistons should be same

Pressure = \frac{Force}{Area}Pressure=

Area

Force

\implies \frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{2}}⟹

A

1

F

1

=

A

2

F

2

Here,

F_{1} = FF

1

=F

F_{2} = 8000\: NF

2

=8000N

(Since F= m×a = m×g; 800 kg× 10m/s= 8000 kg-m/s = 8000 N)

(Took g = 10 m/s)

Substitute Values, we get

\implies \frac{F}{10} = \frac{8000}{10×10^{4}}⟹

10

F

=

10×10

4

8000

\implies F = 0.8\: N⟹F=0.8N

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