Question

help me with the 1,2,3,5,7,9 questions only please

Answer 1

Heavy demand.....
1)OA= OB (RADIUS)
SO, Angle OAB = Angle OBA = 30
IN triangle AOB
Angle AOB = 180 - 90
=90

Now, Angle ACB = 1/2AOB (angle in the same segment)
So ACB = 45

2) Angle BAC = Angle 1/2BOC(Angels in same SEGMENT)
So BOC =2* 29 =58

In triangle BOC
OB = OC (RADIUS)
SO OBC = OCB
NOW, 2OCB = 180 - BOC
OCB = 122/2 = 61

3)ABD = ACD (ANGLE IN SAME ARC)

NOW, BA = BD (GIVEN)
SO, BAD=BDA
NOW, 2BAD=180- ABD
OR, BAD = (180- ABD) /2

5)AP=AD( GIVEN)
SO, APD = ADC = 26
NOW, ADC = ABC (ANGLE IN THE SAME ARC)
THEREFORE, ABC = 26 = PBC

IN TRIANGLE PAD
PAD = 180 - 2APD = 180- 52
PAD = 128
NOW,
DAB = 180- PAD (LINEAR PAIR)
SO, DAB = 52
NOW, DAB = BCD (Angles IN SAME ARC)
THEREFORE, BCD=52

7) 140 + X = 180 (CYCLIC QUADRILATERAL)
SO, X = 40

Y + Y = 180 (CYCLIC QUADRILATERAL)
SO, Y = 90

9) OC = BC (GIVEN)
COB = CBO = 22
DCO = COB + CBO (EXTERIOR ANGLE)
SO, DCO = 44

OC = OD (RADIUS)
OCD = CDO = 44
DOA = 44 + 22 = 66 (EXTERIOR ANGLE)

DCA = 1/2DOA = 33
SO, OCA = 44-33 = 11