Question

Help me with the 14th sum Asap,
Perfect answer with steps will b marked as Brainliest Answer.​

Answer 1

Step-by-step explanation:

We know that the diagonals of a rhombus bisect each other at 90⁰

Let the side of the rhombus be x cm

AO = OC = AC/2 = 24/2 = 12 cm

BO = DO = BD/2 = 10/2 = 5 cm

Using Pythagoras theorem

x

2 = 122 + 52

x

2 = 144 + 25

x

2 = 169

x= √169

x= 13 cm

EXERCISE 11.5

Q7

(e) The diagonals of a square are equal.

(f) The diagonals of a square bisect each other at 90 degrees.

(g)The diagonals of a square are perpendicular to each other

(h) All sides of a square are equal .

Q9 Rectangle.

Answer 2

Step-by-step explanation:

We know that the diagonals of a rhombus bisect each other at 90⁰

Let the side of the rhombus be x cm

AO = OC = AC/2 = 24/2 = 12 cm

BO = DO = BD/2 = 10/2 = 5 cm

Using Pythagoras theorem

x

2 = 122 + 52

x

2 = 144 + 25

x

2 = 169

x= √169

x= 13 cm

EXERCISE 11.5

Q7

(e) The diagonals of a square are equal.

(f) The diagonals of a square bisect each other at 90 degrees.

(g)The diagonals of a square are perpendicular to each other

(h) All sides of a square are equal .

Q9 Rectangle.