Question

help me with the question above ...​

Answer 1

Step-by-step explanation:

Given polynomial is:

$\: \: \: \: \: \: \: \: \: \:4 {x}^{2} - 2x + k + 7 \\ \implies \: a {x}^{2} + bx + c \\ a = 4 \\ b - 2 \\ c = k + 7 \\ \because \: \alpha \: and \: \frac{1}{ \alpha } \: are \: zeros \: of \: given \: \\ polynomial \\ hence \\ product \: of \: zeros \\ \alpha \times \frac{1}{ \alpha } = \frac{ c}{a} \\ 1 = \frac{k + 7}{4} \\ 4 = k + 7 \\ 4 - 7 = k \\ k \: = - 3$

Answer 2

Given

a= 4

b= - 2

c= k+7

A/q,

a*1/a= c/a

4*1/4=k+7/4

4=k+7

or, k=-7+4

or, k= - 4