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4. I) We know, a straight line=180°. To find out x= 180°-45°= 135°
ii) Angle X= 40° (vertically opposite angles)
Angle y (or z whichever you choose)= 180-40= 140°.
Angle z (angle y if you choose z), = 140° (vertically opposite angles).
iii) in this case, we can see:
Angle on left hand side=90° (by the sign we can understand that)
Angle on RHS= 55°. 90+55= 145°.
x=180-145° = 35°
iv) z= 47+90= 137°. 180-137°= 43°
x= z=43° (vertically opposite angles)
y= 180-43°= 137°
v) I can't solve that without the value of x but for the others, z= x+40, y= x-10
vi) z= 180-60= 120°
x=60° (vertically opposite angles)
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