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Answer:
1. b²-4ac=0
2. 8 cm
Step-by-step explanation:
Solution 1.
For a quadratic equation ax² +bx+c=0, b²-4ac is its discriminant (denoted with D).
If value of D(b²-4ac) is equal to zero,
then the roots of a quadratic equation are equal and real.
Solution 2.
Take a circle with centre O.
Draw a chord AB and draw OC perpendicular
to chord AB.
Length of chord AB = 12 cm
Radius of circle OB = 10 cm
BC = AB/2 = (12/2) cm = 6 cm
Distance between centre of circle O and
chord AB = OC
Applying Pythagoras theorem in right angled
triangle,
OB² = OC² + BC²
→OC² = OB² - BC²
→OC² = (10)² - (6)² cm = (100 - 36)cm = 64 cm
→OC =√64 = √8×8 cm
→OC = 8 cm (Ans.)