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Answer:
Empirical Formula of a salt is the simplest positive integer ratio of all the components of the salt or the compound. We are given Sodium=29.1%, Sulphur=40.51% and Oxygen=30.38%.
We first calculate the mass in grams of each of the elements. For this, we consider the mass of each element= percentage given. So we get:
Sodium= 29.1 gm
Sulphur= 40.51 gm
Oxygen= 30.38 gm
We now calculate the molar mass of each of the elements. We know that the molar weight of sodium= 23 gm, sulphur= 32 gm and oxygen= 16 gm.
We now calculate the molar mass of the three elements:
Sodium or Na= (29.1× 1mol Na)÷23= 1.26 mol Na
Sulphur or S= (40.51×1mol S)÷32 = 1.26 mol S
Oxygen or O=(30.38 ×1mol O)÷16=1.89 mol O
Now, we divide the molar mass of each element with the smallest molar weight calculated to get an integer value for all the elements.
Na= 1.26/1.26 mol Na= 1
S= 1.26/1.26mol S= 1
O= 1.89/1.26 mol O=1.5
We now have to factorize to get the lowest whole number. Since one solution is 1.5, we will multiply all the solutions by 2.
So we get, Na= 1×2= 2
S= 1×2= 2
O=1.5×2=3
The ratio of the elements Na:S:O= 2:2:3