Math, asked by minion22, 3 months ago

help me with this answer by doing the working asli whoever answers correctly will be marked as brainliest and whoever answers incorrectly with be reported and those who don't know the answer kindly ignore it and don't make attempt doing wrong answers​

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Answered by Gurudas03
1

Answer:

Pocket Money (x)= 10, 20, 30, 40

Number of students (f) = 4, 8, 12, 6

Total number of students = Sum (f) = 4+8+12+6 = 30

fx = 10x4, 20x8, 30x12, 40x6

fx = 40, 160, 360, 240

Sum (fx) = 40+160+360+240 = 800

a) Mean Pocket Money = Sum (fx)/ Sum (f)

= 800/30 = 80/3 = 26.67

b) Mode = Pocket money got by most number of students

= 12 students (most) get Rs.30

therefore, Mode = Rs.30

c) Median = Middle terms of 30 students

= Average of 15th and 16th students

15th Student and 16th student will get Rs.30

Therefore Median = (30+30)/2 = 60/2 = 30

Answered by santhdoll
0

Answer:

mean= 26.6 median=30 mode =30

Step-by-step explanation:

to find mean pocket money

sum fo the observation

/

number of the observation

800/30=26.6 something

therefore means=26.6

mode ==reapeting number =30

median= middle term of 30 students=average of 15th Student

we will get 15th and 16th observation

therefore 30+30/2=60/2=30

so median of students is 30

think this will helpfull for you plese vote me

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