Help Me With This Arithmetic Progression Sum.
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1
Given T1 = 32 = a T2 = 29 d = 29 - 32 = -3
Tn = a +( n- 1 )d
Here Tn = last term = 5
Thus
5 = 32 + (n - 1) (-3)
5 - 32 = -3n + 3
- 27 = -3n + 3
-30 = - 3n
n = 10
Pls mark the answer brainliest
Tn = a +( n- 1 )d
Here Tn = last term = 5
Thus
5 = 32 + (n - 1) (-3)
5 - 32 = -3n + 3
- 27 = -3n + 3
-30 = - 3n
n = 10
Pls mark the answer brainliest
Answered by
4
Ahola!
Here's your answer:
( please check the attachment for worked out solution)
AP: 32,29,26.............5
a= 32
d= -3
An=5
An=a+(n-1)d
2=32-3n
-30=-3n
n=10
So your answer is that there are 10 rows of rose plants in the rose garden..
Hope this helps!!
~@BERRYLIPS❤
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OK BYE YOU MAD
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