Question

Help me with this guys.​

Answer 1

hey mate here is ur solution
Laba =125°
it forms a liner pair
so,125°+x=180°
x=180°-125°=. 55°
now,Lace=130°
130°+x=180°
x=180°-130°=50°
in triangle abc
55°+50°+x=180°(angle sum property of traiangle)
105°+x=180°
x=180°-105°=. 75°
hence,Lbac =75°
pls mark it brainalist

Answer 2

heyDUDE,
Here is your answer

I couldn't find angle sign therefore using angle as /_

/_ABD = 125°

/_ABD + /_ABC = 180° (Linear Pair )

125° + /_ABC = 180°

/_ABC = 180° - 125°

/_ABC = 55°

Now,

/_ACE = 130°

/_ACE + /_ACB = 180° (Linear pair )

130° + /_ACB = 180°

/_ACB = 180° - 130°

/_ACB = 50°

So,

/_BAC + /_ABC + /_ACB = 180° (Angle sum property of ∆ )

/_BAC + 55° + 50° = 180°

/_BAC = 180° - 105°

/_BAC = 75°