Question

help me ..with this one .​

Answer 1

X=b1c2-b2c1/a1b2-a2b1

....

Y=c1a2-c2a1/a1b2-a2b1

Answer 2

Answer:

-4 5. 4. -4

-20 1. -12. -20

$\frac{x}{ - 80 - 48} = \frac{y}{ - 4 + 100} = \frac{1}{ - 60 - 4} \\ \frac{x}{ - 128} = \frac{y}{96} = \frac{1}{ - 64} \\ therefore..... \\ \frac{x}{ - 128} = \frac{1}{ - 64} \\ x = 2 \\ \\ and \\ \frac{y}{96} = \frac{1}{ - 64} \\ y = \frac{96}{ - 64} = \frac{ - 3}{2}$