Question

Help me with this please................

Answer 1

Answer:

Step-by-step explanation:

→let keep another perpendicular as D

∠ACD=180-90-60=30°

∠BAC=180-45-90=45

→We get that triangle ABC as isosceles triangle(∵in ABC traingle is isosceles triangle beacause of angle are equal.)

→Then by isosceles triangle property AB=AC

$\bigstar$Then pythagoras theorem

$\sqrt{AB^2+BC^2}=AC$

AB=AC

$\sqrt{2AB^2} =10$

$\sqrt{2}$AB=10

AB=5$\sqrt{2}$=AC

→We know that ∠ACD=30°

Tan30°=AD/DC

1/√3=AD/DC

DC=√3AD

$\sqrt{AD^2+DC^2} =AC$

2AD=10

AD=5

DC=5√3

PERIMETER=5+5√3+5root2+5root2

AREA of triangle ABC=1/2x5root2x5root2=25

AREA of triangle ADC=1/2X5X5ROOT3=25ROOT3/2

Add=25+25root3/2