Help me with this please. The question is the 11th one.
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sorry for this
because i want points for give questions in brain ly
Answered by
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Answer:
f(x) = x³+px²-5x+q
ATP
f(-1) = -1³+p×-1²-5×-1+q=8(since x+1 gives a remainder 8)
-1+p+5+q=8
p+q=4_____(i)
also given
x+2 is a factor of the function
f(-2)= -2³+p×-2²-5×-2+q=0
-8+4p+10+q=0
4p+q=-2______(ii)
subtracting (i) from (ii) we get
4p+q=-2
(-)p. (-)q=-4
3p = -6
p= -2
putting value of p in eq (i) we get
-2+q=4
q=4+2=6
therefore,p=-2 and q=6
Now,
x+3)x³-2x²-5x+6(x²-5x+10
(-)x³(-)3x²
-5x²-5x+6
(+)5x²(+)15x
10x+6
(-)10x(-)30
-24
hence the remainder is -24
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