Question

Help me with this pls

Answer 1

Answer:

First of all name the triangle as ∆ABC with angle B =90°. We need to find BC

After that , By applying Pythagoras theorem,

AB^2 + BC^2= AC^2

=> BC^2= AC^2- AB^2

=> BC=√(AC^2-AB^2)

=> BC= √20^2-18^2

=> BC= √76

Step-by-step explanation:

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