Question

Help me with this problem​

Answer 1

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✍ (4) 20( √3 + 1)

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EXPLANATION —

Net Force along vertical components-

$mg = Tcos Q + Tcos @$

Here given,

Q = 45°

@ = 30°

m= 4 kg

g = 10 m/s²

$= > 4 \times 10 = T \cos(45) + T \cos(30)$

$= > 40 = \frac{T}{ \sqrt{2} } + \frac{T \sqrt{3} }{2}$

On solving

T = 20 (√3+1)

Kindly check the calculations, i think i made mistake somewhere

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Answer 2

Answer:

this is the right answer