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hey mate here is ur ans
AB is parallel to CD. ....given
also
P & Q are mid points to AC & RC
so. AP =PC. & RQ = QC
now In triangle ARC.
AP /PC = RQ / QC. (bcoz AP = PC & RQ = QC)
by inverse of basic proportionalty therom
PQ ll AB
but AB ll CD. so
P Q ll CD
hence PQ ll AB ll CD
AB is parallel to CD. ....given
also
P & Q are mid points to AC & RC
so. AP =PC. & RQ = QC
now In triangle ARC.
AP /PC = RQ / QC. (bcoz AP = PC & RQ = QC)
by inverse of basic proportionalty therom
PQ ll AB
but AB ll CD. so
P Q ll CD
hence PQ ll AB ll CD
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