Question

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Answer 1

Answer:

Let the 3 years ago machine value = P Rate of depreciates, R = 10% Time, n = 3 years Now, Value = P (1 + R/100)n [Where, P = Present value R = Annual interest rate n = Time in years] ∴ Value = P (1 - 10/100)n [∵ Rate decreases] ⇒ 291600 = P (1 - 1/10)3 ⇒ 291600 = P (9/10)3 ⇒ 291600 = P × 729/1000 ⇒ P = 291600 × 1000/729 ⇒ P = 400 × 1000 ⇒ P = 400000 ∴ Initial value of machine is Rs.400000.Read more on Sarthaks.com - https://www.sarthaks.com/1118151/the-value-machine-depreciates-rate-annum-was-purchased-years-ago-its-present-value-291600

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Answer 2

Answer:

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