Question

help me with this question​

Answer 1

Answer:

Hope it helps...... please mark it BRAINLIEST ✌️

Answer 2

2.

${27}^{y} = {3}^{1 + y} \\ { ({3}^{3}) }^{y} = {3}^{1 + y} \\ {3}^{3y} = {3}^{1 + y} \\ y + 1 = 3y \\ 3y - y = 1 \\ 2y = 1 \\ y = \frac{1}{2}$

1.

$\frac{ {8}^{x + 1} }{ {2}^{x} } = 16 \\ \frac{ ({{2}^{3})}^ {x + 1} }{ {2}^{x} } = 16 \\ \frac{{2}^{3x + 3} }{ {2}^{x} } = 16 \\ {2}^{3x + 3 - x} = 16 \\ {2}^{2x + 3} = {2}^{4} \\ 2x + 3 = 4 \\ 2x = 4 - 3 = - 1 \\ 2x = - 1 \\ x = \frac{ - 1}{2}$

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