Question

help me with this question​

Answer 1

Step-by-step explanation:

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SUM OF INTERIOR ANGLE = (n-2)180°

EACH INTERIOR ANGLE = (n-2)180°/n

SUM OF EXTERIOR ANGLE = 360°

EACH EXTERIOR ANGLE = 360°/n

BY CONDITION

360°/n + 140° = (n-2)180°/n

360° + 140n° = (n-2)180°

360° + 140n° = 180n° - 360°

40n° = 720°

n = 18

THEREFORE NO OF SIDES = 18

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