Physics, asked by rajputanthal1981, 5 hours ago

help me with this question experts. its very urgent . i request no irrelevant answers plz​

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Answered by nilesh7060
2

Answer:

16m/s

EXPLANATION:

average speed is equal to total distance upon total time

let the radius of circle be 'r'

distance covered in half circle is equal to Pi r

so it's time will be pi-r upon 10 second

10th third quarter distance is equal to Pi r by2

so it's time will be Pi up our upon 120 seconds

final quarter the distance travelled is pi are upon 2

the time for third quarter will be pi r upon 60 seconds

average speed=2pi r/(pi r/10)+(pi r/120)+(pi r/60)

2*120/15=16 metre per second

Answered by Anonymous
2

Answer: 16 m/s.

Explanation:

Average speed = (Total distance)/(Total time)

Let, total distance = x + x + x + x = 4x

(if one quarter = x)

∵ t = s/v,

Average speed = (4x)/(2x/10 + x/60 + x/30) m/s

=> v(av) = (4)/[(12 + 1 + 2)/60]

=> v(av) = 60 × 4 / 15

=> v(av) = 4 × 4

=> v(av) = 16 m/s

So, average speed of the motorcycle = 16 m/s.

More: Average speed for given 2 speed values, say a and b, is 2ab/(a + b). Similarly, for 3 speed values, use 3abc(ab + bc + ac).

And if, two velocity values are given and they are changed uniformly, use v bar = (v + u)/2.

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