Question

Help me with this question :)

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Answer 1

Answer:

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Answer 2

According to the given question ,

A body is thrown vertically upwards and it rises to a height of 10 m

i.e h = 10m

Let the initial velocity of the body be( u ) and the final velocity of the body be ( v )

Note : The velocity of the body at the highest point is always zero

Hence , final velocity of the body = 0

(a)

By using the third kinematic equation ,

$\bigstar\displaystyle \boxed{ \green {\mathtt{ {v}^{2} = {u}^{2} + 2as}}}$

Substituting the given values in the above equation we get ,

$\rightarrow\mathtt{ {v}^{2} = {u}^{2} - 2gs}$

$\rightarrow\mathtt{{u}^{2} = 2gs}$

$\rightarrow\mathtt{ {u}^{2} = 2 \times 10 \times 10}$

$\rightarrow\mathtt{u = \sqrt{200} }$

$\boxed{ \red{ \mathtt{u = 10 \sqrt{2} \frac{m}{s}}}}$

(b)

By using the first kinematic equation ,

$\bigstar\displaystyle \boxed{ \green {\mathtt{v = u + at}}}$

Substituting the given values in the above equation we get ,

$\rightarrow\mathtt{ v = u - gt}$

$\rightarrow\mathtt{ u = gt}$

$\rightarrow\mathtt{ t = \frac{u}{g} }$

$\rightarrow\mathtt{ t = \frac{10√2}{10} }$

$\boxed{ \red{ \mathtt{t = √2 \: s}}}$

Answer:

• the velocity with which the body was thrown upward= 10 √2 m/s
• time taken by the body to reach the highest point= √2sec