Question

Help me with this question pls!!

Answer 1

Let AB be the observer
 CD be the tower.
Now, AB = 1.2 m
 BD = 28.2 m
Let CD = h m
Draw AL⊥CD
.Let ∠CAL = 60°
Now, LD = AB = 1.2 m; 
AL = BD = 28.2 m
Now, CL = (h−1.2) m
In ∆CLA, tan 60° = CLAL⇒3√ = h−1.228.2⇒h−1.2 = 28.23√⇒h = 28.23√ + 1.2 = 28.2 ×1.73 + 1.2 = 48.786 + 1.2 = 49.986 m


Please follow the diagram and refer to the solution!
hope this helps!! cheers!! (:

Answer 2

here is Ur answer....I hope u will understand