Question

help me with this question plzz​

Answer 1

Step-by-step explanation:

the ans is

x0 1 2

y3 8 13

taxi fare for first km = Rs. 8

taxi fare for subsequent distance = Rs. 5

total distance covered =x

total fare =y

the fare for first km =Rs.8

fare for (x-1) kilometer =5 ( x - 1 )

the total fare y =5 (x-1) +8

y=5(x - 1 ) + 8

y = 5x + 3

y= 5x + 3 is the required linear equation .

the equation is

y= 5x + 3 ...(1)

putting the value x = 0 in (1)

y= 5 X 1 + 3

y= 5 + 3 = 8. the solution is ( 1,8)

putting the value x = 2 in (1)

y= 5 X 2 + 3

y= 10 + 3 = 13 . so the solution is (2,13)

Answer 2

i think.. it's right dear..