Question

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Answer 1

Answer:

-1

Step-by-step explanation:

Given,

$\frac{ \tan( \frac{\pi}{2} + \alpha) \sec(\pi - \alpha ) \sin( - \alpha ) }{ \sin(\pi + \alpha ) \cot(2\pi - \alpha ) \csc( \frac{\pi}{2} + \alpha ) }$

$= \frac{ ( - \cot( \alpha ) )( - \sec( \alpha ))( - \sin( \alpha )) }{( - \sin( \alpha ))( - \cot( \alpha )) \sec( \alpha ) }$

$= - 1$

Hope this will help you....!