Question

Help me with this sum please.​

Answer 1

Answer:

well it's simple

${sec}^{2}(90 - 0) = { \cosec }^{2} 0 \\ and \: {tan}^{2}(90 - 0) = { \cot }^{2} 0 \\ therefore \: {sec}^{2}(90 - 0) + {tan}^{2}(90 - 0) = { \cosec }^{2} 0 + { \cot }^{2} 0 \:$