help me with this sum question 6a
Attachments:
Answers
Answered by
1
put 0 wherever k is written and then solve it
(3k+1)x² +2(k+1)x+k=0
(3×0+1)x² + 2 (0+1)x+0=0
0+1x²+0+1x+0=0
1x²+1x+0=0
2x³+0=0
2x³=0
k=2x³
(3k+1)x² +2(k+1)x+k=0
(3×0+1)x² + 2 (0+1)x+0=0
0+1x²+0+1x+0=0
1x²+1x+0=0
2x³+0=0
2x³=0
k=2x³
Answered by
2
Answer:
×The value of k is -1/2 and 1
Step-by-step explanation:
The following is the answer to your question ::-
HOPE IT HELPS YOU!!
Attachments:
Similar questions