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25a2- 35a+12
25a2-20a-15a+12
5a(5a-4)-3(5a-4)
(5a-3)(5a-4)
Hence (5a-3)and (5a-4) may be the possible length and breadth respectively.
Similarly , 35y2+13y-12 = (7y-3) (5y+4)
Hence (7y-3) and (5y+4) may be the possible length and breadth respectively.
25a2-20a-15a+12
5a(5a-4)-3(5a-4)
(5a-3)(5a-4)
Hence (5a-3)and (5a-4) may be the possible length and breadth respectively.
Similarly , 35y2+13y-12 = (7y-3) (5y+4)
Hence (7y-3) and (5y+4) may be the possible length and breadth respectively.
Answered by
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☺️☺️here is your answer ✨
1) 25a² - 35a +12
25a² - 15a - 20a +12 = 0
5a(5a-3) - 4(5a-3) = 12
so, = 4/5 , 3/5
will be possible expressions for length and breadth.
2) 35y²+13y-12 = 0
by , quadratic formula -
-b+-√b² -4ac\ 2a
= -13+- √13²-4(35)(-12)\2(35)
= -13 +- (43)/70
so, 2 cases =
-13+43/70 = 3/7
or , -13-43/70 = -8/10 = -4/5
will be the given length and breadth..
hope it helps u ✌️✌️✌️✌️✌️☺️ ☺️
1) 25a² - 35a +12
25a² - 15a - 20a +12 = 0
5a(5a-3) - 4(5a-3) = 12
so, = 4/5 , 3/5
will be possible expressions for length and breadth.
2) 35y²+13y-12 = 0
by , quadratic formula -
-b+-√b² -4ac\ 2a
= -13+- √13²-4(35)(-12)\2(35)
= -13 +- (43)/70
so, 2 cases =
-13+43/70 = 3/7
or , -13-43/70 = -8/10 = -4/5
will be the given length and breadth..
hope it helps u ✌️✌️✌️✌️✌️☺️ ☺️
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