Question

HELP MY SIS...
${a}^{2} + \frac{ {b}^{2} }{4} + \frac{ {c}^{2} }{9} + ab + \frac{bc}{3} + \frac{2}{3} ca$
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Answer 1

Answer:

256

Step-by-step explanation:

(a+b+c)² =a²+b²+c²+2ab+2bc+2ca

(a+b+c)² =a²+b²+c²+2(ab+bc+ca)

Put the value of a²+b²+c² and ab+bc+ca which is given in the question then

(a+b+c)²= 250+2*3

(a+b+c)²= 256

then , a+b+c= (256)½

Hence a+b+c= 16

Since 16 is the square root of 256

Answer 2

Hope it helps ❤️

Good afternoon Adi ^_^