Question

Help ne with these two sums.
Question 9 and 10 both please explain​

Answer 1

Answer:

Let the cost of 1 chair be x & cost of 1 table be y.

ATQ

3x +2y = 2140…(1)

cost of 1 chair(x) =( y -120)

x = y-120

Put the value of x in eq 1

3x +2y = 2140

3(y-120)+ 2y = 2140

3y - 360 +2y = 2140

3y +2y = 2140 +360

5y = 2500

y = 2500/5= 500

Cost of 1 table = rs 500

Cost of 1 chair(x) = y -120 = 500 - 120 = rs 380.

Hence, the Cost of a table is ₹500 and the Cost of a chair is rs 380.

Let the wieght of the bag of sugar be x… now, the question says that the bag of rice wieghs 20 kg more than the bag of sugar, so the wieght of the bag of rice = (x + 20) kg

Now, 50 kg is added to the second bag, so the wieght of the bag of sugar = (x + 50)kg

Now, the wieght of the bag of sugar is twice the bag of rice, so,

=) 2 (X + 20) = (x + 50)

=) 2x + 40 = x + 50

=) 2x - x = 50 - 40

=) x = 10

We know, the bag of rice wieghs (x+20) kg or (10+20)= 30 kg :)

Hope it helps you

MARK ME THE BRAINLIEST AND FOLLOW